Occupations sql hackerrank. Reload to refresh your session.

Occupations sql hackerrank e. May 10, 2024 · SQL. name) Dr from occupations D where occupation = 'Doctor'), Ss As(select S. Jan 10, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Apr 19, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Problem. Here, we have columns- name, occupation and rank (generated for each occupation using ROW_NUMBER() function) Since 1st it is partitioned by occupation, it gives values sorted in asc order according to occupation and then sorts the names HackerRank SQL track solutions. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Nov 17, 2024 · SELECT MIN (CASE WHEN occupation = ' Doctor ' THEN name END) AS Doctor, MIN (CASE WHEN occupation = ' Professor ' THEN name END) AS Professor, MIN (CASE WHEN occupation = ' Singer ' THEN name END) AS Singer, MIN (CASE WHEN occupation = ' Actor ' THEN name END) AS Actor--You can use MIN or MAX up to you b / c It doesn ' t effect Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. See more Annotated solutions to HackerRank's SQL domain questions. right? i'm easy member too. :) For those of you who do not get how to number the rows, just think of it as : the first Doctor i. Except for it's giving Occupation name as the 1st column, I don't understand why this is not working, can some explain please. Once you complete step 3, add "ORDER BY Name" (Refer above code on where to add Order by clause). Jun 27, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. I'm new to SQL and struggled to find the solution for about 2 days in my spare time. Create a HackerRank account Feb 6, 2023 · Firstable, you use ROW_NUMBER() to order the names with the same profession. name) Pr from occupations P where occupation = 'Professor') , Ds As (select D. SQL. Skills. Sql Server. Step 1: Number the rows within each occupation. - SQL-Hackerrank-Challenge-Solutions/Advanced Select/Occupations. //This will return Max of each row number (each row number will have only 1 occupations and rest will be null)// Select Max(case when occupation='Doctor' then name end) as Doctor, Max(case when occupation='Professor' then name end) as Professor, Max(case when occupation='Singer' then name end) as Singer, Max(case when occupation='Actor' then Jan 10, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Advanced Select. Jul 20, 2024 · SET @max_rows:= (SELECT COUNT(DISTINCT Occupation) FROM OCCUPATIONS);. from occupations) Jul 4, 2022 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Solved. Reload to refresh your session. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. The output Jan 3, 2024 · /*Solution with Oracle Sql*/ WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) Feb 24, 2024 · I think this is a much simpler MySQL solution: CREATE VIEW OccupationsView AS SELECT ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS row_num, Occupation, Name FROM OCCUPATIONS; SELECT MAX(IF(Occupation = 'Doctor', Name, NULL)) AS Doctor, MAX(IF(Occupation = 'Professor', Name, NULL)) AS Professor, For me it always helps to turn the "subquery" into its own query and take a look at its output, as follows: SELECT Name, Occupation, (ROW_NUMBER() OVER( PARTITION BY Occupation ORDER BY Name )) AS rn FROM Occupations Jan 3, 2024 · /*Solution with Oracle Sql*/ WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' THEN Name END) You signed in with another tab or window. Sep 24, 2024 · SQL. name, rank() over( order by P. Occupation AND a. Mar 18, 2023 · SQL. Contribute to ndleah/SQL-Hackerrank-Challenge-Solutions development by creating an account on GitHub. UNION ALL SELECT occupation_count_summary, 2 FROM TotalOccupationCount Apr 16, 2023 · SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name ELSE NULL END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name ELSE NULL END) AS Actor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Solve Challenge. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. 50%. THIS IS FOR SQL SERVER SELECT [Doctor],[Professor],[Singer],[Actor] FROM( SELECT ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS [ROWNUMBER], * FROM OCCUPATIONS) AS Dec 20, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. NAME, SingTable. Name > b. Aug 6, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Name ASC) RowNum FROM OCCUPATIONS o WHERE o. Input Format. if it is wrong, let me know~ ^^. Most ones can solve the problem but i can't. Jul 4, 2024 · MySQL: SELECT MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS 'Doctor', MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS 'Professor', MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS 'Singer', MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS 'Actor' FROM (SELECT Name, Occupation, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. name_group_rank), (SELECT Name FROM partitioned_cte WHERE Occupation = Mar 29, 2024 · SQL Server WITH DOCTOR AS ( SELECT NAME , ROW_NUMBER () OVER ( ORDER BY NAME ASC ) NUM FROM OCCUPATIONS WHERE OCCUPATION = ' DOCTOR ' GROUP BY NAME ), PROFESSOR AS ( SELECT NAME , ROW_NUMBER () OVER ( ORDER Solutions for all SQL challenges on HackerRank executed on MySQL and MS SQL Server. Name, (SELECT COUNT(*) FROM Occupations AS b WHERE a. Apr 3, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Name) AS rank FROM Occupations AS a I guess the row number function provides each distinct occupation with separate row numbers, like 1,2,3 for doctor and again 1,2,3 for professor since it was partitioning by occupation. Create a HackerRank account Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. professor FROM (SELECT name AS doctor, ROW_NUMBER() OVER (ORDER BY name) AS r1 FROM occupations WHERE occupation = 'doctor' ) AS a right join (SELECT name AS professor, ROW_NUMBER() OVER (ORDER BY name) AS r2 FROM occupations WHERE For example, when you group by ID 1, you will get the first row with occupation "Doctor", and the first row with occupation "Singer" and so on with the other two occupations, this will force the correct values to come first. Jul 30, 2024 · with temp as (select* ,ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS id from OCCUPATIONS ) , pvt_temp as (select * From temp pivot (max(name) for occupation in (Doctor, Professor, Singer, Actor) )as pvtCols )select Doctor, Professor, Singer, Actor from pvt_temp Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Codes of Algorithms/Coding Competitions on Hackerrank with Python, JavaScript, C++ and SQL - HackerRank/Occupations. Works with Mysql: # with base_tab as ( select case when occupation ='Doctor' then name else null end as doctor, case when occupation='Professor' then name else null end as professor, case when occupation='Singer' then Name else null end as singer, case when Occupation='Actor' then Name else null end as actor from OCCUPATIONS), doctor_tab as ( select row_number() Jan 23, 2023 · Hi All, could anyone support me to know why the below query is wrong? SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE 'NULL' END) Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE 'NULL' END) Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE 'NULL' END) Singer, MAX(CASE WHEN occupation Jun 28, 2023 · With CTE as (SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) as rn from Occupations) Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Jun 2, 2024 · with doctor as ( select name as name, row_number() over (order by name) as row_num from occupations where occupation = 'doctor' order by name asc ), prof as( select name as name, row_number() over (order by name) as row_num from occupations where occupation = 'professor' order by name asc ), singer as( select name as name, row_number() over I used a similar query, but my order for the professors is incorrect. Occupation, a. Occupation = ' Doctor '), Professors AS (SELECT o. I am using idn to combine the result properly. Create a HackerRank account Jul 23, 2024 · SELECT MAX(CASE WHEN occupation = 'doctor' THEN name ELSE NULL END) AS doctor, MAX(CASE WHEN occupation = 'professor' THEN name ELSE NULL END) AS professor, MAX(CASE WHEN occupation = 'singer' THEN name ELSE NULL END) AS singer, MAX(CASE WHEN occupation = 'actor' THEN name ELSE NULL END) AS actor FROM ( May 13, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Do you know anything about JOIN here? 0 | Parent Permalink. Apr 27, 2024 · Here I see the answer is quite tough for me to solve. Nov 30, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. You mister just saved my day. doctor, b. r2, a. Julia gets a rownumber = 2 , and so on. WITH CTE AS ( SELECT Occupation, Name, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' Jan 4, 2023 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Sep 25, 2024 · SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name END) AS Actor FROM ( SELECT name, occupation, ROW_NUMBER() OVER Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Oct 10, 2024 · WITH ctc AS (SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS row_num FROM occupations ) SELECT MAX(CASE WHEN occupation ='Doctor' THEN name END)AS Doctor, MAX(CASE WHEN occupation ='Professor' THEN name END)AS Professor, MAX(CASE WHEN occupation ='Singer' THEN SQL. Oct 24, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Select MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS Actor FROM ( Select *, ROW_NUMBER() OVER SQL. Hard. The below SQL query works fine on SQL Server. MS SQL Code: SELECT Doctor, Professor, Singer, Actor FROM ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) as rn FROM Occupations ) AS src_table PIVOT ( MAX(Name) Nov 28, 2023 · WITH RankedNames AS ( SELECT Name, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY Name) AS NameRank FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' THEN Name END) AS Professor, Dec 24, 2024 · in SQL SERVER, code is . Jul 23, 2024 · WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = SQL. You switched accounts on another tab or window. Oct 8, 2024 · this will work for oracle sql : SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE NULL END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE NULL END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE NULL END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name ELSE Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH LEBALTABLE AS Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Jenny Ashley Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Name) AS rank FROM Occupations AS a Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Sample Output. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. i think so, i know group by is working with aggregate functions(min, max, count, etc. name, rank() over( order by S. MS sql server. So add Jul 11, 2024 · WITH ranked AS ( SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS rn FROM OCCUPATIONS ), pivoted AS ( SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN Sep 11, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. professor,f. @arati1626 @himanshimathpal1 To clarify this, first you need to create row number of each record partitioned by its occupation in the entity Nov 26, 2024 · select e. sql at main · qanhnn12/SQL-Hackerrank-Challenge-Solutions Jan 5, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In the first statement it doesn't matter if Min or Max is used as long as the occupations are ordered by Name, they are used to select actual values rather than NULL. Note: Print NULL when there are no more names May 4, 2024 · with d as (select name, row_number over as id from occupations where occupation = ' doctor ' order by name), p as (select name, row_number over as id from occupations where occupation = ' professor ' order by name), s as (select name, row_number over as id from occupations where occupation = ' singer ' order by name), a as (select name, row Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. I translated your solution to something that works in MS SQL. Create a HackerRank account Group by is used to convert columns to rows. Note: Print NULL when there are no more names corresponding to an occupation. Since some of us here may not be fimilar with sql, I'll start with where I left so you get the whole picture. UNION ALL SELECT occupation_count_summary, 2 FROM TotalOccupationCount Jul 5, 2024 · MYSQL: this code contains 2 CTEs, first grouping by occupation and numbering names by alphbetical order second CTE It uses a CASE statement within the MAX function to conditionally aggregate names based on the Occupation. 0 | Create a HackerRank account Problem. We first need to assign a unique number to each row within each occupation. In mysql: select Doctor, Professor, Singer, Actor. from (select name, occupation, rownumber() over (partition by occupation order by name asc) rn from occupations) May 8, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Easy. so to get the value of pivot column, we have to use 'min'. Sep 30, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. So you obtain something like: Eve | Actor |1 Jennifer |Actor |2 Ketty | Actor |3 Samantha |Actor |4 Aamina |Doctor|1 Julia |Doctor|2 Priya |Doctor |3 And so on for the other professions. SELECT a. Leaderboard. SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, MAX(CASE WHEN Dec 24, 2024 · MYSQL SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name END) AS Actor FROM ( SELECT name, occupation, @rownum:= Nov 25, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. 4 days ago · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. row2: the second in Doctor; the secondin Professor; the second in Singer; the second in Actor. ROW_NUMBER(): Assigns a unique number to each row. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Simply i wrote this code in SQL Server and its working fine: Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SELECT DocTable. As stated below 'min()/max() will return a name for specific index and specific occupation. See the input, output, and explanation of the problem, and the code solution provided by CodingBroz. Apr 14, 2024 · MY SQL Solution. name) Sr from occupations S where occupation = 'Singer'), AA As Name ASC) RowNum FROM OCCUPATIONS o), Doctors AS (SELECT o. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) Jun 8, 2024 · (select case when occupation = 'doctor' then name end as 'doctor', case when occupation = 'professor' then name end as 'professor', case when occupation = 'singer' then name end as 'singer', case when occupation = 'actor' then name end as 'actor', row_number() over (partition by occupation order by name) as n. But join keyword is not working in this hackerrank. ). These recursive functions you constructed {@r1:=@r1+1} is basically the same as creating a rank column partitioned by Occupation:with cte as ( select RANK() OVER (PARTITION BY Occupation ORDER BY Name) as Rank, case when Occupation='Doctor' then Name else null end as May 17, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Name, ROW_NUMBER OVER (ORDER BY o. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Codes of Algorithms/Coding Competitions on Hackerrank with Python, JavaScript, C++ and SQL - ynyeh0221/HackerRank SELECT CONCAT(GROUP_CONCAT(IF(Occupation = 'Doctor', Name, NULL) ORDER BY Name SEPARATOR ',')) AS Doctor, CONCAT(GROUP_CONCAT(IF(Occupation = 'Professor', Jul 13, 2020 · Occupations. Hiring developers? Log In; Sign Up; Prepare. NAME, ProfTable. May 3, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In this SELECT Statement im grabbing Names, Occpation and Row_Numer counts Ordering by Name as the problem asks i. doctor,e. Occupation = ' Professor '), Finally the code aggregates the rows together using the group by RowNumber and the min statement. Then same property I need in result is rollnumber . name, rank() over( order by D. Means When it finds actor it increments the value a for doctor it increments the value d for professor it increments the value p for singer it increments the value s then I used group by so that I can combine the all for count parallely means by this I wanna show the first of all the occupation's name together so that it can take a proper table form. e Alice Doctor 1 Sam Doctor 2 Juile Singer 1 Zach Singer 2 etc. singer,f. Really good stuff. Status. select [Doctor] as Doctor, [Professor] as Professor, [Singer] as Singer, [Actor] as Actor from (select name, occupation, ROW_NUMBER() OVER ( PARTITION BY Occupation ORDER BY Jun 3, 2024 · SELECT MAX(CASE WHEN occupation='doctor' THEN NAME ELSE NULL END) AS doctor, MAX(CASE WHEN occupation='professor' THEN NAME ELSE NULL END) AS professor, MAX(CASE WHEN occupation='singer' THEN NAME ELSE NULL END)AS singer, MAX(CASE WHEN occupation='actor' THEN NAME ELSE NULL END)AS actor FROM ( . chat-gpt will refers you dynamic queries or some ways like my query because there is no pivot operator like Microsoft SQL Server in MySQL. I use this query With Ps As (select P. Discussions. Aamina gets a rownumber = 1, the second Doctor i. Jun 30, 2023 · The goal is to transform the data from a single Occupation column to multiple columns: Doctor, Professor, Singer, and Actor, with names listed underneath each occupation and sorted alphabetically. select doctor, professor, singer, actor . Note: Print NULL when there are no more names corresponding to an Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The OCCUPATIONS Jul 1, 2024 · AS occupation_count_summary FROM occupations GROUP BY occupation ) SELECT result FROM ( SELECT formatted_occupation AS result, 1 AS sort_order FROM OccupationSummary. Contribute to edaaydinea/HackerRank development by creating an account on GitHub. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. - raleighlittles/HackerRank-SQL /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. NAME FROM (SELECT OCCUPATION, [NAME], ROW_NUMBER() OVER(PARTITION BY OCCUPATION ORDER BY [NAME] ASC) AS ID FROM OCCUPATIONS WHERE OCCUPATION = 'Doctor') As DocTable FULL OUTER JOIN FROM (SELECT ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) as rn, name, occupation FROM occupations) PIVOT (MAX(name) FOR OCCUPATION IN ('Doctor' as Doctor, Jul 1, 2024 · AS occupation_count_summary FROM occupations GROUP BY occupation ) SELECT result FROM ( SELECT formatted_occupation AS result, 1 AS sort_order FROM OccupationSummary. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective This repository includes HackerRank Solutions. SELECT Occupation, MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. . actor from (SELECT b. Dec 25, 2022 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. We use cookies to Nov 29, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. NAME, ActTable. Learn how to solve the Occupations problem in SQL using MySQL set and case statements. Jan 27, 2024 · -- Step 1: Assigning Row Numbers within each Occupation WITH NameLists AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS NameOrder FROM Occupations ) You signed in with another tab or window. Oracle. Dec 3, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Apr 28, 2024 · WITH t1 AS (SELECT name AS doctor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Doctor '), t2 AS (SELECT name AS professor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Professor '), t3 AS (SELECT name AS singer, ROW_NUMBER OVER Nov 8, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. select Doctor, Professor, Singer, Actor from (select *, row_number () Create a HackerRank account WITH partitioned_cte AS (SELECT Name, Occupation, row_number OVER(PARTITION BY Occupation ORDER BY Name) AS name_group_rank FROM OCCUPATIONS) SELECT (SELECT Name FROM partitioned_cte WHERE Occupation = 'Doctor' AND name_group_rank = t. Dec 30, 2024 · with cte as (select *, row_number over (partition by Occupation order by Name) as ct from Occupations) select min (case when Occupation = ' Doctor ' then Name else null end) as ' Doctor ', min (case when Occupation = ' Professor ' then Name else null end) as ' Professor ', min (case when Occupation = ' Singer ' then Name else null end) as Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. You are viewing a single comment's thread. Source: HackerRank. sql at master · ynyeh0221/HackerRank Oct 24, 2024 · This approach is easy to use and understandable. Mar 13, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Great explanation. Medium. Jul 13, 2020 · Occupations. Create a HackerRank account Dec 16, 2024 · SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name END) AS Actor FROM ( SELECT Name, Occupation, ROW_NUMBER() Sep 9, 2024 · Step2 : Recombine rows : use group by (need at least one same property ) Because we want the result looks like this row1: the first in Doctor; the first in Professor; the first in Singer; the first in**Actor**. Unsolved. Submissions. Oct 22, 2024 · WITH doctors AS (SELECT name AS doctorName, ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY name) AS rn FROM OCCUPATIONS WHERE occupation = ' Doctor '), professors AS (SELECT name AS professorName, ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY name) AS rn FROM OCCUPATIONS mysql version : SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name ELSE NULL END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name ELSE NULL END) AS Actor Aug 18, 2024 · SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE NULL END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE NULL END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE NULL END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name ELSE NULL END) AS Actor FROM Sep 3, 2023 · My SQL Server solution, using PIVOT and CTE :- WITH numbered_names ( Name , Occupation , RN ) AS ( SELECT Name , Occupation , ROW_NUMBER () OVER ( PARTITION BY Occupation ORDER BY Name ) AS RN FROM Occupations ) SELECT Doctor , Professor , Singer , Actor FROM numbered_names PIVOT ( MAX ( Name ) Dec 20, 2024 · MAX is used to pick the name in a grouped row. May 2, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. I even can understand the answer given in discussion section. You signed out in another tab or window. The output should consist of four columns (Doctor, Professor, Singer, and Actor) in that specific order, with their respective names listed alphabetically under each column. Occupations. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. We use cookies to ensure you have the best browsing experience on our website. SQL (Basic) SQL (Intermediate) SQL (Advanced) Difficulty. In my solution I have solved it but my solution is not flexible but It is very easy to understand let me explain you here in the question I have constructed 4 new tables each tables consisting of names of specific occupation and rno which contains the serial number of record. PARTITION BY Occupation: Resets the row number for each occupation group. The output column headers should be Doctor, Professor, Singer, and Actor, Jul 23, 2023 · HackerRank SQL Interview Question: Level Medium. WITH RankedOccupations AS ( -- Assign a row number to each name based on their occupation and sort them alphabetically SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) -- Pivot the table by occupations SELECT Ex: #237 [Solved] Occupations in SQL solution in Hackerrank Intermediate Ex: #238 [Solved] Binary Tree Nodes in SQL solution in Hackerrank Intermediate Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. Create a HackerRank account Be part of a 23 million-strong community of developers. Occupation = b. The output column headers should be Dec 28, 2022 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be Doctor, Professor, Singer, Mar 2, 2021 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. fwery vpejc acmhbe mbrgq ktf isu fpvnly entuh jzig crymi